Welcome to Lotto the Smart Way to Play

In the posts below I list a very simple way to increase your chances of winning any pick 6 type Lottery game anywhere in the world. In fact this is the only way to increase your chances of winning! All worthwhile systems selling on the internet are based on the facts you will learn below and my site is completely free of charge - of course if you use this info and win millions then I wouldn't knock back a donation :-). Please click the follow button to keep up to date and ask your friends to do likewise. If you are new to this blog then please go to Part 1 to read all details of the system. Thankyou

Sunday, January 9, 2011

(Part 5) The good news

Still waiting for the good news? Well, let’s see if we can brighten things up a little. How do we increase our chances of winning? The obvious answer is to play systems entries. I know, you don't need to be told to play systems entries in order to increase your chances of winning, of course you don’t but I still have to mention it. Systems entries obviously increase your chances of winning because you are playing more numbers and covering more combinations. They range from a system 7 up to system 18 or more. Obviously the bigger the system the more you increase your chances of winning. The catch is of course that it costs a great deal more to play. As you can see from the table below, if you played a system 18 (based on NSW Lotto) it would cost you $10710.00 to play – way out of most peoples reach.
 
System
Equivalent
Cost

Games
to play
7
7
 $           4.40
8
28
 $         16.60
9
84
 $         48.60
10
210
 $       121.50
11
462
 $       267.00
12
924
 $       534.00
13
1716
 $       990.00
14
3003
 $    1732.50
15
5005
 $    2887.50
16
8008
 $    4624.00
17
12376
 $    7146.00
18
18564
 $    10710.0
Note: These prices are a guide only
and will vary depending on which
lottery you play.


This table can of course be expanded to include all systems right up to 45 and beyond. The method for working out the number of combinations in each system is known as “the binominal co-efficient of 6 out of S, where S represents the system being played” Therefore working out the number of combinations for a system 21, the calculation would look like this:

21 x 20 x 19 x 18 x 17 x 16
6 x 5 x 4 x 3 x 2 x 1


Or 39,070,080 divided by 720 which equals 54,264 combinations. A system, 22 would be 22 x 21 x 20 x 19 x 18 x 17 divided by 720 = 74,613 combinations and so on for each system.

So how do we go about playing systems entries while still keep the playing cost within our reach? I’m glad you asked. The answer of course is that we play abbreviated systems.

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